%I #4 Jun 03 2017 15:27:27
%S 1,3,5,7,9,10,12,14,16,18,20,22,24,25,27,29,31,33,34,36,38,40,42,44,
%T 46,48,49,51,53,55,57,59,61,63,64,66,68,70,72,73,75,77,79,81,83,85,87,
%U 88,90,92,94,96,97,99,101,103,105,107,109,111,112,114,116
%N Positions of 0 in A287773; complement of A287777.
%C 0 < n*r - a(n) < 2 for n >= 1, where r = (-3 + 3*sqrt(5))/2.
%H Clark Kimberling, <a href="/A287774/b287774.txt">Table of n, a(n) for n = 1..10000</a>
%t s = Nest[Flatten[# /. {0 -> {0, 1}, 1 -> {0}}] &, {0}, 10] (* A003849 *)
%t w = StringJoin[Map[ToString, s]]
%t w1 = StringReplace[w, {"0" -> "010", "1" -> "101"}]
%t st = ToCharacterCode[w1] - 48 (* A287773 *)
%t Flatten[Position[st, 0]] (* A287774 *)
%t Flatten[Position[st, 1]] (* A287777 *)
%Y Cf. A287773, A287777.
%K nonn,easy
%O 1,2
%A _Clark Kimberling_, Jun 03 2017