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A287394 Domination number for camel's graph on a 2 X n board. 3
0, 2, 4, 6, 6, 6, 6, 6, 6, 6, 8, 10, 12, 12, 12, 12, 12, 12, 12, 14, 16, 18, 18, 18, 18, 18, 18, 18, 20, 22, 24, 24, 24, 24, 24, 24, 24, 26, 28, 30, 30, 30, 30, 30, 30, 30, 32, 34, 36, 36, 36, 36, 36, 36, 36, 38, 40, 42, 42, 42, 42, 42, 42, 42, 44, 46, 48, 48 (list; graph; refs; listen; history; text; internal format)
OFFSET
0,2
COMMENTS
Minimum number of camels (from Tamerlane chess and fairy chess) required to dominate a 2 X n board.
LINKS
Wikipedia, Camel (chess)
FORMULA
a(n) = 2*(floor((n+6)/9) + floor((n+7)/9) + floor((n+8)/9))).
G.f.: 2*x / ((1 - x)^2*(1 + x^3 + x^6)). - Colin Barker, May 26 2017
a(n) = 2*A093390(n+6).
EXAMPLE
For n=4 we need a(4)=6 camels to dominate a 2 X 4 board.
MATHEMATICA
Table[2*(Floor[(i+6)/9]+Floor[(i+7)/9]+Floor[(i+8)/9]), {i, 0, 67}]
PROG
(Python) [2*(int((i+6)/9)+int((i+7)/9)+int((i+8)/9)) for i in range(68)]
(PARI) concat(0, Vec(2*x / ((1 - x)^2*(1 + x^3 + x^6)) + O(x^100))) \\ Colin Barker, May 27 2017
CROSSREFS
Sequence in context: A054584 A049041 A092337 * A302754 A225369 A296511
KEYWORD
nonn,easy
AUTHOR
David Nacin, May 24 2017
STATUS
approved

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Last modified April 25 03:15 EDT 2024. Contains 371964 sequences. (Running on oeis4.)