

A287056


a(n) is such that A100827(n) = A082917(n  a(n))  1, or 1 if there is no corresponding term.


1



1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 1, 2, 2, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 2, 2, 1, 3, 3, 3, 3, 1, 4, 4, 1, 5, 5, 5, 5, 5, 5, 5, 5, 5, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 2, 2, 2, 2, 2, 2
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OFFSET

1,23


COMMENTS

Most of the known terms of A100827 are 1 less than a term in A082917, and conversely. This sequences looks at the location in the sequence of the corresponding terms. Negative terms do not occur among the known terms of this sequence. When a(n+1) is different from a(n) (and both are nonnegative), there are a(n+1)a(n) terms in one of the sequences that aren't in the other. With some irregularities, this sequence generally gradually increases at first, reaching a(49)=5. Then there are 9 a(n)=5, followed by 20 a(n)=4, followed by 30 a(n)=3, and then a(n)=2 for n=108 to 229. What is the behavior of the rest of the sequence? Does it stay at a(n)=2?


LINKS

Jud McCranie, Table of n, a(n) for n = 1..229


EXAMPLE

Examples: A100827(6)=47, A082917(5)=47+1, so a(6) = 65 = 1. A100827(23)=779, A082917(21)=779+1, so a(23) = 2321 = 2.


CROSSREFS

Cf. A082917, A100827.
Sequence in context: A064284 A030409 A030407 * A098357 A165735 A083888
Adjacent sequences: A287053 A287054 A287055 * A287057 A287058 A287059


KEYWORD

sign


AUTHOR

Jud McCranie, May 18 2017


STATUS

approved



