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%I #4 May 17 2017 11:34:32
%S 1,2,4,5,8,9,12,13,15,16,19,20,23,24,26,27,30,31,34,35,38,39,41,42,45,
%T 46,49,50,52,53,56,57,60,61,64,65,67,68,71,72,75,76,78,79,82,83,86,87,
%U 89,90,93,94,97,98,101,102,104,105,108,109,112,113,115,116
%N Positions of 0 in A286804; complement of A286806.
%C a(n) - a(n-1) is in {1,2,3} for n>=2, and a(n)/n -> (6 + sqrt(2))/4.
%H Clark Kimberling, <a href="/A286805/b286805.txt">Table of n, a(n) for n = 1..10000</a>
%e As a word, A286804 = 0010011001100100110011..., in which 0 is in positions 1,2,4,5,8,9,...
%t s = Nest[Flatten[# /. {0 -> {0, 0, 1}, 1 -> {0}}] &, {0}, 16]; (* Pell word, A171588 *)
%t w = StringJoin[Map[ToString, s]];
%t w1 = StringReplace[w, {"000" -> ""}];
%t st = ToCharacterCode[w1] - 48 ; (* A286804 *)
%t Flatten[Position[st, 0]]; (* A286805 *)
%t Flatten[Position[st, 1]]; (* A286806 *)
%Y Cf. A171588, A286804, A286806.
%K nonn,easy
%O 1,2
%A _Clark Kimberling_, May 16 2017
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