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%I #7 Aug 04 2018 04:11:15
%S 1,5,8,16,17,21,24,28,29,37,40,48,49,57,60,64,65,69,72,80,81,85,88,92,
%T 93,101,104,108,109,113,116,124,125,133,136,144,145,149,152,156,157,
%U 165,168,176,177,185,188,192,193,197,200,208,209,217,220,228,229
%N Positions of 0 in A286055; complement of A286057.
%C Conjecture: a(n)/n -> 4.
%H Clark Kimberling, <a href="/A286056/b286056.txt">Table of n, a(n) for n = 1..10000</a>
%e As a word, A286055 = 011101101111111001..., in which 0 is in positions 1,5,8,16,...
%t s = Nest[Flatten[# /. {0 -> {0, 1}, 1 -> {1, 0}}] &, {0}, 9] (* A010060 *)
%t w = StringJoin[Map[ToString, s]]
%t w1 = StringReplace[w, {"010" -> "0"}]
%t st = ToCharacterCode[w1] - 48 (* A286055 *)
%t Flatten[Position[st, 0]] (* A286056 *)
%t Flatten[Position[st, 1]] (* A286057 *)
%Y Cf. A010060, A286055, A286057.
%K nonn,easy
%O 1,2
%A _Clark Kimberling_, May 08 2017
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