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A285989
a(0) = 0, a(n) = Sum_{0<d|n, n/d odd} d^4 for n > 0.
7
0, 1, 16, 82, 256, 626, 1312, 2402, 4096, 6643, 10016, 14642, 20992, 28562, 38432, 51332, 65536, 83522, 106288, 130322, 160256, 196964, 234272, 279842, 335872, 391251, 456992, 538084, 614912, 707282, 821312, 923522, 1048576, 1200644, 1336352, 1503652, 1700608
OFFSET
0,3
COMMENTS
Multiplicative because this sequence is the Dirichlet convolution of A000035 and A000583 which are both multiplicative. - Andrew Howroyd, Aug 05 2018
FORMULA
a(n) = A051001(n)*16^A007814(n) for n >= 1. - Robert Israel, Apr 30 2017
From Amiram Eldar, Nov 01 2022: (Start)
Multiplicative with a(2^e) = 2^(4*e) and a(p^e) = (p^(4*e+4)-1)/(p^4-1) for p > 2.
Sum_{k=1..n} a(k) ~ c * n^5, where c = 31*zeta(5)/160 = 0.200904... . (End)
Dirichlet g.f.: zeta(s)*zeta(s-4)*(1-1/2^s). - Amiram Eldar, Jan 08 2023
MAPLE
f:= n -> add((n/d)^4, d = numtheory:-divisors(n/2^padic:-ordp(n, 2))); # Robert Israel, Apr 30 2017
MATHEMATICA
{0}~Join~Table[DivisorSum[n, Mod[#, 2] (n/#)^4 &], {n, 36}] (* Michael De Vlieger, Aug 05 2018 *)
PROG
(PARI) a(n)={sumdiv(n, d, (d%2)*(n/d)^4)} \\ Andrew Howroyd, Aug 05 2018
CROSSREFS
Sum_{0<d|n, n/d odd} d^k: A002131 (k=1), A076577 (k=2), A007331 (k=3), this sequence (k=4), A096960 (k=5), A096961 (k=7), A096962 (k=9), A096963 (k=11).
Sequence in context: A151502 A030693 A308249 * A231303 A218082 A159501
KEYWORD
nonn,mult
AUTHOR
Seiichi Manyama, Apr 30 2017
STATUS
approved