|
%I #4 May 06 2017 00:27:01
%S 1,2,3,5,6,7,8,9,11,12,13,15,16,18,19,20,21,22,23,25,26,27,28,29,31,
%T 32,33,34,35,36,38,39,41,42,43,45,46,47,48,49,51,52,53,55,56,58,59,60,
%U 61,62,63,65,66,68,69,70,72,73,74,75,76,78,79,80,81,82,83
%N Positions of 0 in A285963; complement of A285965.
%C Conjecture: a(n)/n -> 4/5.
%H Clark Kimberling, <a href="/A285964/b285964.txt">Table of n, a(n) for n = 1..10000</a>
%e As a word, A285963 = 00010000010001001..., in which 0 is in positions 1,2,3,5,6,...
%t s = Nest[Flatten[# /. {0 -> {0, 1}, 1 -> {1, 0}}] &, {0}, 9] (* Thue-Morse, A010060 *)
%t w = StringJoin[Map[ToString, s]]
%t w1 = StringReplace[w, {"11" -> "0"}]
%t st = ToCharacterCode[w1] - 48 (* A285963 *)
%t Flatten[Position[st, 0]] (* A285964 *)
%t Flatten[Position[st, 1]] (* A285965 *)
%Y Cf. A010060, A285963, A285965.
%K nonn,easy
%O 1,2
%A _Clark Kimberling_, May 05 2017
|
