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Positions of 1 in A285668; complement of A285669.
3

%I #4 May 02 2017 20:49:01

%S 1,2,4,5,6,8,9,10,11,12,14,15,16,18,19,20,22,23,24,25,26,28,29,30,32,

%T 33,34,36,37,38,40,41,42,44,45,46,47,48,50,51,52,54,55,56,58,59,60,61,

%U 62,64,65,66,68,69,70,72,73,74,75,76,78,79,80,82,83,84

%N Positions of 1 in A285668; complement of A285669.

%C Conjecture: -1 < n*r - a(n) < 4 for n>=1, where r = (1 + sqrt(17))/4.

%H Clark Kimberling, <a href="/A285670/b285670.txt">Table of n, a(n) for n = 1..10000</a>

%e As a word, A285668 = 11011101..., in which 1 is in positions 1,2,4,5,6,8,...

%t s = Nest[Flatten[# /. {0 -> {1, 1}, 1 -> {1, 1, 0, 1}}] &, {0}, 9] (* A285668 *)

%t Flatten[Position[s, 0]] (* A285669 *)

%t Flatten[Position[s, 1]] (* A285670 *)

%Y Cf. A285668, A285669.

%K nonn,easy

%O 1,2

%A _Clark Kimberling_, May 02 2017