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A285481
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Smallest integer radius needed such that an n-dimensional ball has a volume greater than or equal to 1.
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2
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1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3
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OFFSET
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1,13
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LINKS
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FORMULA
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a(n) = ceiling((1/(((Pi^(n/2))/(gamma(1+n/2)))))^(1/n)).
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EXAMPLE
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a(12) = 1 because a 12-ball of radius 1 has a volume of Pi^6/720 = 1.33526..., which is greater than 1.
a(13) = 2. A 13-ball of radius 1 has a volume of just 0.91..., while a 13-ball of radius 2 has a volume of 7459.87...
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MATHEMATICA
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Table[Ceiling[(1/(((Pi^(n/2))/(Gamma[1 + n/2]))))^(1/n)], {n, 10^2}] (* Michael De Vlieger, Apr 24 2017 *)
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PROG
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(PARI) volume(n, r) = ((Pi^(n/2))/(gamma(1+n/2)))*r^n
a(n) = my(k=1); while(1, if(volume(n, k) >= 1, return(k)); k++)
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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