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A285077
Positions of 0 in A285076; complement of A285078.
3
2, 3, 5, 7, 8, 10, 12, 13, 15, 17, 19, 20, 22, 24, 25, 27, 29, 31, 32, 34, 36, 37, 39, 41, 42, 44, 46, 48, 49, 51, 53, 54, 56, 58, 60, 61, 63, 65, 66, 68, 70, 71, 73, 75, 77, 78, 80, 82, 83, 85, 87, 89, 90, 92, 94, 95, 97, 99, 101, 102, 104, 106, 107, 109
OFFSET
1,1
COMMENTS
Conjecture: -1 < n*r - a(n) < 1 for n>=1, where r = 1 + sqrt(1/2).
This conjecture can be proved in the same way as the conjecture on A285074. - Michel Dekking, May 30 2017
Appears to differ from A285074 only at a(1). - R. J. Mathar, Apr 24 2017
This is correct, and follows from the fact that A285073 and A285076 are equal except for the first two terms which are respectively 0,1 and 1,0. (See Comments for A285073.) - Michel Dekking, May 30 2017
LINKS
EXAMPLE
As a word, A285076 = 100101001010..., in which 0 is in positions 2,3,5,7,8,...
MATHEMATICA
s = Nest[Flatten[# /. {0 -> {1, 0}, 1 -> {0, 1, 0}}] &, {0}, 13]; (* A285076 *)
Flatten[Position[s, 0]]; (* A285077 *)
Flatten[Position[s, 1]]; (* A285078 *)
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Clark Kimberling, Apr 19 2017
STATUS
approved