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A284906
Positions of 0 in A284905; complement of A284907.
3
1, 4, 5, 8, 9, 11, 13, 16, 17, 20, 21, 23, 25, 28, 29, 31, 34, 35, 37, 40, 41, 44, 45, 47, 49, 52, 53, 56, 57, 59, 61, 64, 65, 67, 70, 71, 73, 76, 77, 80, 81, 83, 85, 88, 89, 91, 94, 95, 98, 99, 101, 103, 106, 107, 109, 112, 113, 116, 117, 119, 121, 124, 125
OFFSET
1,2
COMMENTS
2n - a(n) is in {0,1} for n >=1.
See the comments of A285250 for a proof of this conjecture. - Michel Dekking, Oct 07 2020
LINKS
EXAMPLE
As a word, A284905 = 011001..., in which 0 is in positions 1,4,5,8,9,...
MATHEMATICA
s = Nest[Flatten[# /. {0 -> {0, 1}, 1 -> {1, 0, 0, 1}}] &, {0}, 6] (* A284905 *)
Flatten[Position[s, 0]] (* A284906 *)
Flatten[Position[s, 1]] (* A284907 *)
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Clark Kimberling, Apr 17 2017
STATUS
approved