A284902 Positions of 0 in A284901; complement of A284903.

1, 4, 5, 6, 8, 9, 10, 11, 13, 15, 18, 19, 20, 21, 23, 25, 27, 30, 31, 32, 33, 36, 37, 38, 39, 42, 43, 44, 46, 47, 48, 49, 51, 53, 55, 58, 59, 60, 61, 64, 65, 66, 67, 70, 71, 72, 73, 76, 77, 78, 80, 81, 82, 83, 85, 87, 89, 92, 93, 94, 96, 97, 98, 99, 101, 103

Offset

1,2

Comments

Conjecture: -3 < n*r - a(n) < 3 for n >= 1, where r = (3+sqrt(3))/3.

Links

Clark Kimberling, Table of n, a(n) for n = 1..10000

Example

As a word, A284901 = 01100010..., in which 0 is in positions 1,4,5,6,8,9,11,...

Mathematica

s = Nest[Flatten[# /. {0 -> {0, 1}, 1 -> {0, 0, 1, 1}}] &, {0}, 6] (* A284901 *)
Flatten[Position[s, 0]]  (* A284902 *)
Flatten[Position[s, 1]]  (* A284903 *)

Crossrefs

Cf. A284901, A284903.

Sequence in context: A088720 A134848 A061578 * A023851 A285279 A091242

Adjacent sequences: A284899 A284900 A284901 * A284903 A284904 A284905

Keyword

nonn,easy

Author

Clark Kimberling, Apr 16 2017

Status

approved