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a(n) = rad(A280864(n)).
1

%I #23 Apr 11 2017 08:17:13

%S 1,2,2,3,6,2,5,10,6,3,7,14,2,11,22,6,15,10,6,21,14,26,13,17,34,30,15,

%T 19,38,2,23,46,6,3,5,35,42,6,29,58,10,55,33,39,26,22,77,7,31,62,10,65,

%U 78,6,37,74,14,21,51,34,30,15,41,82,2,43,86

%N a(n) = rad(A280864(n)).

%C By definition, all terms are squarefree (see A007947); repeated terms here are the squarefree kernels of A280864(n).

%C All even squarefree numbers appear infinitely often.

%C 1 appears only at a(1).

%C Even terms appear consecutively in pairs, each pair followed by one or more odd terms.

%C Conjecture: all odd squarefree numbers > 1 appear infinitely often. If so, then A280864 is a permutation of the natural numbers.

%C Theorem: a(n) = b(n-1)*b(n) where b = A280738. - _N. J. A. Sloane_, Apr 11 2017

%e a(61) = 30 because A280864(61) = 60, and rad(60) = 30.

%Y Cf. A280864, A284311, A284457, A007947, A280738.

%K nonn

%O 1,2

%A _Bob Selcoe_, Apr 02 2017