%I
%S 1,4,7,8,10,13,15,16,18,22,25,26,28,32,34,35,37,40,43,44,46,49,51,52,
%T 54,58,60,61,63,66,69,70,72,76,79,80,82,85,87,88,90,94,97,98,100,104,
%U 106,107,109,112,115,116,118,122,125,126,128,131,133,134,136
%N Positions of 0 in A284627; complement of A284685.
%C a(n)  a(n1) is in {1,2,3,4} for n>=2. Conjecture: a(n)/n > 9/4.
%H Clark Kimberling, <a href="/A284684/b284684.txt">Table of n, a(n) for n = 1..10000</a>
%e As a word, A284627 = 0110110010110100101110..., in which 0 is in positions 1,4,7,8,10,...
%t s = Nest[Flatten[# /. {0 > {0, 1}, 1 > {1, 0}}] &, {0}, 9] (* A010060 *)
%t w = StringJoin[Map[ToString, s]]
%t w1 = StringReplace[w, {"0011" > "1"}]
%t st = ToCharacterCode[w1]  48 (* A284627 *)
%t Flatten[Position[st, 0]] (* A284684 *)
%t Flatten[Position[st, 1]] (* A284685 *)
%Y Cf. A010060, A284627, A284685.
%K nonn,easy
%O 1,2
%A _Clark Kimberling_, May 10 2017
