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A284681 Positions of 0 in A284680; complement of A284682. 3

%I #13 Oct 21 2023 02:49:36

%S 2,3,4,9,10,11,13,14,15,17,18,19,21,22,23,28,29,30,35,36,37,42,43,44,

%T 49,50,51,53,54,55,57,58,59,61,62,63,68,69,70,72,73,74,76,77,78,80,81,

%U 82,87,88,89,91,92,93,95,96,97,99,100,101,106,107,108,110

%N Positions of 0 in A284680; complement of A284682.

%C Conjecture: a(n)/n -> (7 + sqrt(13))/6.

%H Clark Kimberling, <a href="/A284681/b284681.txt">Table of n, a(n) for n = 1..10000</a>

%e As a word, A284680 = 1000111100010001000..., in which 0 is in positions 2,3,4,9,...

%t s = Nest[Flatten[# /. {0 -> {1}, 1 -> {1, 0, 0, 0}}] &, {0}, 8] (* A284680 *)

%t Flatten[Position[s, 0]] (* A284681 *)

%t Flatten[Position[s, 1]] (* A284682 *)

%Y Cf. A284680, A284682.

%K nonn,easy

%O 1,1

%A _Clark Kimberling_, Apr 11 2017

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Last modified April 23 10:29 EDT 2024. Contains 371905 sequences. (Running on oeis4.)