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 A284169 a(n) is the least k such that sigma(binomial(m,k)) = sigma(binomial(m-1,k-1)) + sigma(binomial(m-1,k)) where m = A284168(n). 1
 1, 2, 5, 5, 9, 3, 17, 13, 21, 10, 18, 6, 28, 32, 33, 26, 20, 27, 28, 19, 12, 41, 34, 42, 54, 25, 5, 28, 84, 22, 40, 5, 54, 44, 56, 25, 29, 86, 81, 89, 88, 134, 10, 71, 148, 69, 87, 27, 91, 92, 18, 128, 23, 51, 52, 153, 108, 202, 112, 138, 58, 201, 141, 162, 176, 77, 4 (list; graph; refs; listen; history; text; internal format)
 OFFSET 1,2 COMMENTS Consider the triangle formed by replacing each m in Pascal's triangle with sigma(m). Then this sequence consists of the least column indices of the terms that are equal to the sum of its NW and N neighbors, as in a Pascal triangle. LINKS EXAMPLE Here is the triangle also described in A074801. 1, 1, 1, 1, 3, 1, 1, 4, 4, 1, 1, 7, 12, 7, 1, 1, 6, 18, 18, 6, 1, On row index 3, we have 4 which is the sum of 1 and 3 its NW and N neighbors, this is A284168(1). The corresponding column index is 1, so a(1) = 1. PROG (PARI) T(n, k) = sigma(binomial(n, k)); isokT(n, k) = T(n-1, k-1) + T (n-1, k) == T(n, k); isokn(n) = for (k=1, n-1, if (isokT(n, k), return(1))); listak(nn) = for (n=1, nn, for (k=1, n-1, if (isokT(n, k), print1(k, ", "); break))); CROSSREFS Cf. A000203, A007318, A074801, A284168. Sequence in context: A014249 A168071 A145420 * A152781 A200242 A062553 Adjacent sequences:  A284166 A284167 A284168 * A284170 A284171 A284172 KEYWORD nonn AUTHOR Michel Marcus, Mar 21 2017 STATUS approved

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Last modified December 15 09:05 EST 2019. Contains 329995 sequences. (Running on oeis4.)