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A283896
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Relative of Hofstadter Q-sequence: a(-88) = 89, a(-87) = 2; thereafter a(n) = a(n-a(n-1)) + a(n-a(n-2)).
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5
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91, 2, 180, 2, 180, 2, 180, 2, 180, 2, 180, 2, 180, 2, 180, 2, 180, 2, 180, 2, 180, 2, 180, 2, 180, 2, 180, 2, 180, 2, 180, 2, 180, 2, 180, 2, 180, 2, 180, 2, 180, 2, 180, 2, 180, 2, 180, 2, 180, 2, 180, 2, 180, 2, 180, 2, 180, 2, 180, 2, 180, 2, 180, 2, 180, 2, 180, 2, 180, 2, 180, 2, 180, 2, 180
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OFFSET
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1,1
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COMMENTS
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In calculating terms of this sequence, use the convention that a(n)=0 for n<=-89.
Sequences like this are more naturally considered with the first nonzero term in position 1. But this sequence would then begin with 89 terms consisting entirely of alternating 2 and 89.
This sequence has exactly 2467 terms, since a(2467)=0 and computing a(2468) would refer to itself.
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LINKS
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MAPLE
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CROSSREFS
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KEYWORD
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nonn,fini,full
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AUTHOR
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STATUS
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approved
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