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A283674
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Square array A(n,k), n>=0, k>=0, read by antidiagonals, where column k is the expansion of Product_{j>=1} 1/(1-x^j)^(j^(k*j)) in powers of x.
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4
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1, 1, 1, 1, 1, 2, 1, 1, 5, 3, 1, 1, 17, 32, 5, 1, 1, 65, 746, 298, 7, 1, 1, 257, 19748, 66418, 3531, 11, 1, 1, 1025, 531698, 16799044, 9843707, 51609, 15, 1, 1, 4097, 14349932, 4295531890, 30535636881, 2187941520, 894834, 22, 1, 1, 16385, 387424586, 1099526502508, 95371863221411, 101591759812967, 680615139257, 17980052, 30
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OFFSET
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0,6
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LINKS
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FORMULA
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G.f. of column k: Product_{j>=1} 1/(1-x^j)^(j^(k*j)).
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EXAMPLE
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Square array begins:
1, 1, 1, 1, ...
1, 1, 1, 1, ...
2, 5, 17, 65, ...
3, 32, 746, 19748, ...
5, 298, 66418, 16799044, ...
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MAPLE
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with(numtheory):
A:= proc(n, k) option remember; `if`(n=0, 1, add(add(
d*d^(k*d), d=divisors(j))*A(n-j, k), j=1..n)/n)
end:
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MATHEMATICA
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A[n_, k_] := If[n==0, 1, Sum[Sum[d*d^(k*d), {d, Divisors[j]}] *A[n - j, k], {j, n}] / n]; Flatten[Table[A[d - n, n], {d, 0, 10}, {n, d, 0, -1}]] (* Indranil Ghosh, Mar 17 2017 *)
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PROG
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(PARI) A(n, k) = if(n==0, 1, sum(j=1, n, sumdiv(j, d, d*d^(k*d)) * A(n - j, k))/n);
{for(d=0, 10, for(n=0, d, print1(A(n, d - n), ", "); ); print(); ); } \\ Indranil Ghosh, Mar 17 2017
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CROSSREFS
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KEYWORD
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AUTHOR
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STATUS
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approved
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