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A282816
Number of inequivalent ways to color the faces of a cube using at most n colors so that no two opposite sides have the same color.
2
0, 0, 1, 11, 76, 340, 1135, 3101, 7336, 15576, 30405, 55495, 95876, 158236, 251251, 385945, 576080, 838576, 1193961, 1666851, 2286460, 3087140, 4108951, 5398261, 7008376, 9000200, 11442925, 14414751, 18003636, 22308076, 27437915, 33515185, 40674976, 49066336
OFFSET
0,4
COMMENTS
Also the number of inequivalent ways to color the corners of an octahedron using at most n colors so that no two opposite corners have the same color.
FORMULA
a(n) = n*(n-1)*(n^4-2*n^3+n^2+8)/24.
G.f.: -x^2*(1+4*x+20*x^2+4*x^3+x^4)/(x-1)^7 . - R. J. Mathar, Feb 23 2017
EXAMPLE
For n = 2 we get a(2) = 1 way to color the faces of a cube with two colors so that no two opposite sides have the same color.
MATHEMATICA
Table[(8n(n-1) + n^3(n-1)^3) /24, {n, 0, 35}]
PROG
(PARI) a(n) = n*(n-1)*(n^4-2*n^3+n^2+8)/24 \\ Charles R Greathouse IV, Feb 22 2017
CROSSREFS
Cf. A282817, A047780 (face colorings without restriction).
Sequence in context: A287330 A282384 A092225 * A055901 A036427 A122589
KEYWORD
nonn,easy
AUTHOR
David Nacin, Feb 21 2017
STATUS
approved