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A282816
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Number of inequivalent ways to color the faces of a cube using at most n colors so that no two opposite sides have the same color.
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2
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0, 0, 1, 11, 76, 340, 1135, 3101, 7336, 15576, 30405, 55495, 95876, 158236, 251251, 385945, 576080, 838576, 1193961, 1666851, 2286460, 3087140, 4108951, 5398261, 7008376, 9000200, 11442925, 14414751, 18003636, 22308076, 27437915, 33515185, 40674976, 49066336
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OFFSET
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0,4
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COMMENTS
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Also the number of inequivalent ways to color the corners of an octahedron using at most n colors so that no two opposite corners have the same color.
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LINKS
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FORMULA
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a(n) = n*(n-1)*(n^4-2*n^3+n^2+8)/24.
G.f.: -x^2*(1+4*x+20*x^2+4*x^3+x^4)/(x-1)^7 . - R. J. Mathar, Feb 23 2017
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EXAMPLE
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For n = 2 we get a(2) = 1 way to color the faces of a cube with two colors so that no two opposite sides have the same color.
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MATHEMATICA
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Table[(8n(n-1) + n^3(n-1)^3) /24, {n, 0, 35}]
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PROG
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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STATUS
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approved
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