

A282745


Irregular triangle read by rows, giving coefficients arising when solving g(n) = f(n)+ f(n1) + f(n2) + f(n3) + f(n4) for f(n).


2



0, 1, 0, 2, 1, 3, 2, 4, 3, 5, 4, 0, 6, 5, 1, 0, 7, 6, 2, 1, 8, 7, 3, 2, 9, 8, 4, 3, 10, 9, 5, 4, 0, 11, 10, 6, 5, 1, 0, 12, 11, 7, 6, 2, 1, 13, 12, 8, 7, 3, 2, 14, 13, 9, 8, 4, 3, 15, 14, 10, 9, 5, 4, 0, 16, 15, 11, 10, 6, 5, 1, 0, 17, 16, 12, 11, 7, 6, 2, 1, 18, 17, 13, 12, 8, 7, 3, 2, 19, 18, 14, 13, 9, 8, 4, 3, 20, 19, 15, 14, 10, 9, 5, 4, 0
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OFFSET

0,4


LINKS

Table of n, a(n) for n=0..104.
H. W. Gould, The inverse of a finite series and a thirdorder recurrent sequence, Fibonacci Quart. 44 (2006), no. 4, 302315. Note that there is a typo in line 2 of Table 4.


EXAMPLE

Triangle begins:
0,
1,0,
2,1,
3,2,
4,3,
5,4,0,
6,5,1,0,
7,6,2,1,
8,7,3,2,
9,8,4,3,
10,9,5,4,0,
11,10,6,5,1,0,
12,11,7,6,2,1,
13,12,8,7,3,2,
14,13,9,8,4,3,
15,14,10,9,5,4,0,
16,15,11,10,6,5,1,0,
17,16,12,11,7,6,2,1,
18,17,13,12,8,7,3,2,
...


CROSSREFS

Cf. A282743, A282744.
Sequence in context: A289439 A213633 A289436 * A097140 A028242 A030451
Adjacent sequences: A282742 A282743 A282744 * A282746 A282747 A282748


KEYWORD

nonn,tabf


AUTHOR

N. J. A. Sloane, Mar 04 2017


STATUS

approved



