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a(n) = A280500(n,A280503(n)).
4

%I #9 Jan 10 2017 19:14:13

%S 1,1,1,2,1,3,1,4,1,1,11,1,13,7,1,8,1,9,19,10,1,11,13,6,25,13,1,7,11,

%T 15,1,16,1,15,13,2,37,1,11,12,41,1,25,22,1,13,47,4,11,25,1,1,19,3,55,

%U 1,13,11,59,5,61,31,1,32,1,33,67,34,69,35,61,36,1,37,13,38,59,39,25,40,81,41,11,42,1,43,87,44,55,45,91,46,1,47,19,24,97,49,1,25,13

%N a(n) = A280500(n,A280503(n)).

%H Antti Karttunen, <a href="/A280504/b280504.txt">Table of n, a(n) for n = 1..8192</a>

%H <a href="/index/Bi#binary">Index entries for sequences related to binary expansion of n</a>

%F a(n) = A280500(n,A280503(n)).

%F Other identities. For all n >= 1:

%F A048720(a(n), A280503(n)) = n.

%o (Scheme) (define (A280504 n) (A280500bi n (A280503 n))) ;; Code for A280500bi given in A280500.

%Y Cf. A048720, A056539, A280500, A280503, A280506.

%Y Cf. A044918 (very likely gives the positions of all ones).

%K nonn,base

%O 1,4

%A _Antti Karttunen_, Jan 09 2017