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A279553
Number of length n inversion sequences avoiding the patterns 110, 210, 120, 201, and 010.
23
1, 1, 2, 5, 15, 50, 178, 663, 2552, 10071, 40528, 165682, 686151, 2872576, 12137278, 51690255, 221657999, 956265050, 4147533262, 18074429421, 79102157060, 347519074010, 1532070899412, 6775687911920, 30052744139440, 133649573395725, 595816470717728
OFFSET
0,3
COMMENTS
A length n inversion sequence e_1e_2...e_n is a sequence of integers where 0 <= e_i <= i-1. The term a(n) counts those length n inversion sequences with no entries e_i, e_j, e_k (where i<j<k) such that e_j <> e_k and e_i >= e_k. This is the same as the set of length n inversion sequences avoiding 010, 110, 120, 201, and 210.
It can be shown that this sequence also counts the length n inversion sequences with no entries e_i, e_j, e_k (where i<j<k) such that e_i <> e_j and e_i >= e_k. This is the same as the set of length n inversion sequences avoiding 010, 100, 120, 201, and 210.
LINKS
Megan A. Martinez, Carla D. Savage, Patterns in Inversion Sequences II: Inversion Sequences Avoiding Triples of Relations, arXiv:1609.08106 [math.CO], 2016.
FORMULA
G.f.: 1 + Series_Reversion(x*A094373(-x)). - Gheorghe Coserea, Jul 11 2018
a(n) ~ c * d^n / (sqrt(Pi) * n^(3/2)), where d = 4.730576939379622099763633264641101585205420756515858657461873... is the greatest real root of the equation 4 - 12*d + 4*d^2 - 24*d^3 + 5*d^4 = 0 and c = 0.3916760466183576202289779130261876915536170330427700961416097... is the positive real root of the equation -5 - 64*c^2 - 33728*c^4 + 209664*c^6 + 93184*c^8 = 0. - Vaclav Kotesovec, Jul 12 2018
D-finite with recurrence: 45*n*(n-1)*a(n) -4*(n-1)*(49*n-66)*a(n-1) +2*(-25*n^2+157*n-264)*a(n-2) +2*(-70*n^2+445*n-714)*a(n-3) -4*(n-6)*(n-13)*a(n-4) -4*(n-6)*(2*n-17)*a(n-5) +8*(n-6)*(n-7)*a(n-6)=0. - R. J. Mathar, Feb 21 2020
EXAMPLE
The length 3 inversion sequences avoiding (110, 210, 120, 201, 010) are 000, 001, 002, 011, 012.
The length 4 inversion sequences avoiding (110, 210, 120, 201, 010) are 0000, 0001, 0002, 0003, 0011, 0012, 0013, 0021, 0022, 0023, 0111, 0112, 0113, 0122, 0123.
MAPLE
a:= proc(n) option remember; `if`(n<4, [1, 1, 2, 5][n+1],
((12*(n-1))*(182*n^3-1659*n^2+4628*n-3756)*a(n-1)
-(4*(91*n^4-1057*n^3+3812*n^2-4046*n-906))*a(n-2)
+(6*(n-4))*(182*n^3-1659*n^2+4901*n-4630)*a(n-3)
-(4*(n-4))*(n-5)*(91*n^2-511*n+690)*a(n-4))
/(5*n*(n-1)*(91*n^2-693*n+1292)))
end:
seq(a(n), n=0..30); # Alois P. Heinz, Feb 22 2017
MATHEMATICA
a[n_] := a[n] = If[n < 4, {1, 1, 2, 5}[[n + 1]], ((12*(n - 1))*(182*n^3 - 1659*n^2 + 4628*n - 3756)*a[n - 1] - (4*(91*n^4 - 1057*n^3 + 3812*n^2 - 4046*n - 906))*a[n - 2] + (6*(n - 4))*(182*n^3 - 1659*n^2 + 4901*n - 4630)*a[n - 3] - (4*(n - 4))*(n - 5)*(91*n^2 - 511*n + 690)*a[n - 4]) / (5*n*(n - 1)*(91*n^2 - 693*n + 1292))]; Table[a[n], {n, 0, 30}] (* Jean-François Alcover, Nov 06 2017, after Alois P. Heinz *)
PROG
(PARI)
seq(N) = my(x='x+O('x^N)); Vec(1+serreverse((-x^3+x^2+x)/(2*x^2+3*x+1)));
seq(27) \\ Gheorghe Coserea, Jul 11 2018
KEYWORD
nonn
AUTHOR
Megan A. Martinez, Dec 15 2016
EXTENSIONS
a(10)-a(16) from Lars Blomberg, Feb 02 2017
a(17)-a(26) from Alois P. Heinz, Feb 22 2017
STATUS
approved