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%I #24 Dec 11 2016 00:23:46
%S 2,4,3,3,8,4,4,12,5,5,16,6,4,6,10,10,7,7,24,8,8,13,13,9,8,9,32
%N Irregular triangle read by rows in which row n lists the semiperimeters of the parts of the symmetric representation of sigma(n).
%F a(n) = A279160(n)/2.
%e Triangle begins:
%e 2;
%e 4;
%e 3, 3;
%e 8;
%e 4, 4;
%e 12;
%e 5, 5;
%e 16;
%e 6, 4, 6;
%e 10, 10;
%e 7, 7;
%e 24;
%e 8, 8;
%e 13, 13;
%e 9, 8, 9;
%e 32;
%e ...
%e For n = 9 the symmetric representation of sigma(9) = 13 has three parts of areas 5, 3, 5 respectively. The perímeters of the parts are 12, 8 and 12, so the 9th row of triangle lists the semiperimeters: 6, 4, 6.
%Y Row sums give A244363.
%Y Cf. A237271 gives the row lengths.
%Y Cf. A000203, A196020, A236104, A235791, A237270, A237591, A237593, A245092, A262626, A279160.
%K nonn,tabf,more
%O 1,1
%A _Omar E. Pol_, Dec 07 2016
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