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a(n) = floor(3/n).
2

%I #13 Mar 21 2017 11:12:30

%S 3,1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,

%T 0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,

%U 0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0

%N a(n) = floor(3/n).

%H <a href="/index/Rec#order_01">Index entries for linear recurrences with constant coefficients</a>, signature (1).

%t Table[Floor[3/n], {n, 105}] (* _Michael De Vlieger_, Nov 24 2016 *)

%o (Magma) [3 div n: n in[1..100]];

%Y Cf. A033322, A033324, ..., A033420, A033421, A033422, A033427, A033426, A033425, A033424, A033423.

%Y This sequence is (ignoring the trailing zeros) the third row of A010766.

%K nonn,easy

%O 1,1

%A _Jason Kimberley_, Nov 23 2016