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A277185
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Odd numbers n such that d(n) divides 2^n-1.
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1
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OFFSET
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1,2
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COMMENTS
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Subsequence of odd terms of A277285.
Sequence is infinite. In particular, n = (21p)^6 for primes p = 5 or p > 7 are such: d(n) = 7^3 divides 2^147 - 1, which in turn divides 2^n - 1. - Max Alekseyev, 30 Sep 2016
Note that there are also other forms. For example, (A002110(6)/2)^6 is a term.
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LINKS
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EXAMPLE
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Odd number 729 is a term because 2^729-1 is divisible by d(729) = 7.
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MATHEMATICA
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Select[Range[1000], Mod[ 2^# - 1, DivisorSigma[0, # ]] == 0 && OddQ[#] &] (* G. C. Greubel, Oct 18 2016 *)
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PROG
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(PARI) is(n) = (2^n-1) % numdiv(n) == 0 && n % 2 == 1;
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CROSSREFS
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KEYWORD
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nonn,more
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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