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a(n) = floor(n*(1+sqrt(5))/Pi).
2

%I #12 Nov 05 2016 08:47:01

%S 0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,

%T 26,27,28,29,30,31,32,33,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49,

%U 50,51,52,53,54,55,56,57,58,59,60,61,62,63,64,65,66,67,69,70

%N a(n) = floor(n*(1+sqrt(5))/Pi).

%H <a href="/index/Be#Beatty">Index entries for sequences related to Beatty sequences</a>

%F a(n) = floor(n*(1+sqrt(5))/Pi).

%e For n = 1000 we have that floor(1000*(1+sqrt(5))/Pi) = floor(1000*1.0300724296...) = floor(1030.0724296...) so a(1000) = 1030.

%p A277112:=n->floor(n*(1+sqrt(5))/Pi): seq(A277112(n), n=0..100); # _Wesley Ivan Hurt_, Oct 31 2016

%t f[n_] := Floor[n*(1+Sqrt[5])/Pi]; Array[f, 100, 0]

%Y Complement of A277113.

%Y Cf. A000796, A001622, A094881, A094882.

%K nonn,easy

%O 0,3

%A _Paulo Romero Zanconato Pinto_, Sep 30 2016