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A275481
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n appears once in c_{m,k} for integers m >= k >= 1 where c_{m,k} = ((n+k)!(n-k+1))/((k)!(n+1)!).
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1
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3, 4, 6, 7, 8, 10, 11, 12, 13, 15, 16, 17, 18, 19, 21, 22, 23, 24, 25, 26, 29, 30, 31, 32, 33, 34, 36, 37, 38, 39, 40, 41, 43, 45, 46, 47, 49, 50, 51, 52, 53, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 66, 67, 68, 69, 70, 71, 72, 73, 74, 76, 78, 79, 80, 81, 82, 83, 84, 85
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OFFSET
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1,1
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COMMENTS
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Integers that appear uniquely in the Catalan triangle, A009766.
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LINKS
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MATHEMATICA
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Block[{T, nn = 85}, T[n_, k_] := T[n, k] = Which[k == 0, 1, k > n, 0, True, T[n - 1, k] + T[n, k - 1]]; Rest@ Complement[Range@ nn, Union@ Flatten@ Table[T[n, k], {n, 2, nn}, {k, 2, n}]]] (* Michael De Vlieger, Feb 04 2020, after Jean-François Alcover at A009766 *)
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PROG
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(Python)
#prints the unique integers less than k
def Unique_Catalan_Triangle(k):
t = []
t.append([])
t[0].append(1)
for h in range(1, k):
t.append([])
t[0].append(1)
for i in range(1, k):
for j in range(0, k):
if i>j:
t[i].append(0)
else:
t[i].append(t[i-1][j] + t[i][j-1])
l = []
for r in range(0, k):
for s in range(0, k):
l.append(t[r][s])
unique = []
for n in l:
if n <= k and l.count(n) == 1 :
unique.append(n)
print sorted(unique)
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CROSSREFS
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KEYWORD
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easy,nonn
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AUTHOR
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STATUS
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approved
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