OFFSET
1,2
COMMENTS
Assuming the Riemann hypothesis, Vaidya proved that Q(n) = 6*n/Pi^2 + O(n^k) for any k > 2/5.
LINKS
Charles R Greathouse IV, Table of n, a(n) for n = 1..1000
A. M. Vaidya, On the order of the error function of the square free numbers, Proc. Nat. Inst. Sci. India Part A 32 (1966), pp. 196-201.
PROG
(PARI) ct=r=0; for(n=1, 1e4, if(issquarefree(n), ct++); t=abs(n/zeta(2)-ct); if(t>r, r=t; print1(n", ")))
CROSSREFS
KEYWORD
nonn
AUTHOR
Charles R Greathouse IV, Aug 07 2016
STATUS
approved