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A274262
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Number of positive integers possessing exactly n Fibonacci representations (A000121).
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1
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1, 2, 4, 6, 8, 12, 12, 18, 20, 24, 20, 44, 24, 36, 48, 54, 32, 76, 36, 88, 72, 60, 44, 156, 72, 72, 100, 132, 56, 208, 60, 162, 120, 96, 144, 316, 72, 108, 144, 312, 80, 312, 84, 220, 304, 132, 92, 540, 156, 280, 192, 264, 104, 460, 240, 468, 216, 168, 116, 116, 120, 180, 456, 486, 288, 520, 132, 352, 264, 624, 140
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OFFSET
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1,2
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LINKS
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FORMULA
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Let p, q, r be distinct primes and k be a positive integer.
If n = p^k then a(n) = 2*(p-1)*(2*p-1)^(k-1).
If n = p*q then a(n) = 6*(p-1)*(q-1).
If n = p^2*q then a(n) = 2*(p-1)*(8*p-5)*(q-1).
If n = p^3*q then a(n) = 2*(p-1)*(2*p-1)*(10*p-7)*(q-1).
If n = p^4*q then a(n) = 6*(p-1)*(2*p-1)^2*(4*p-3)*(q-1).
If n = p^2*q^2 then a(n) = 2*(p-1)*(q-1)*(26*p*q-18*p-18*q+13).
If n = p*q*r then a(n) = 26*(p-1)*(q-1)*(r-1).
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EXAMPLE
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Let phi denote the Euler totient.
The integer p^2*q has 8 multiplicative compositions:
(p^2*q), p^2*q, q*p^2, p*(p*q), (p*q)*p, q*p*p, p*q*p, p*p*q
from which
a(p^2*q) = 2*(3*phi(p^2)*phi(q) + 5*phi(p)^2*phi(q))
follows immediately.
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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