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A271116 Integers n such that round(3^n/12) is divisible by n. 3
1, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 91, 97, 101, 103, 107, 109, 113, 121, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, 199, 211, 223, 227, 229, 233, 239, 241, 251, 257, 263, 269, 271, 277, 281, 283, 293, 307 (list; graph; refs; listen; history; text; internal format)
OFFSET
1,2
COMMENTS
In other words, numbers n such that A015518(n-1) is divisible by n.
This sequence generates prime numbers except 2 and 3.
The first few composite terms in this sequence are 91, 121, 671, 703, 949. Note that they are pseudoprimes to base 3.
Also, numbers k such that 3^(k-1) mod (4*k) = 1. In the first million terms only 908 terms are nonprimes. - David A. Corneth, Oct 02 2020
LINKS
EXAMPLE
5 is a term because round(3^5/12) = 20 is divisible by 5.
6 is not a term because round(3^6/12) = 61 which is not divisible by 6. - David A. Corneth, Oct 02 2020
MATHEMATICA
Select[Range@ 308, Divisible[Round[3^#/12], #] &] (* Michael De Vlieger, Mar 31 2016 *)
PROG
(PARI) f(n) = round(3^n/12);
for(n=1, 1e3, if(f(n) % n == 0, print1(n, ", ")));
(PARI) is(n) = lift(Mod(3, 4*n)^(n-1))==1 \\ David A. Corneth, Oct 02 2020
CROSSREFS
Sequence in context: A348753 A276378 A243292 * A171525 A140475 A171577
KEYWORD
nonn,easy
AUTHOR
Altug Alkan, Mar 31 2016
STATUS
approved

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Last modified April 16 07:08 EDT 2024. Contains 371698 sequences. (Running on oeis4.)