A269970 Factorial-nested interval sequence of 1/e.

2, 1, 2, 3, 1, 2, 2, 1, 3, 2, 1, 2, 4, 1, 2, 1, 2, 2, 2, 1, 1, 1, 2, 3, 2, 4, 1, 2, 2, 1, 2, 2, 3, 2, 2, 2, 1, 2, 1, 1, 2, 1, 1, 1, 1, 2, 2, 2, 2, 2, 3, 2, 2, 2, 1, 2, 1, 1, 2, 1, 1, 1, 1, 1, 1, 1, 1, 2, 1, 1, 1, 4, 3, 1, 1, 1, 1, 1, 1, 1, 2, 2, 3, 1, 1, 3

Offset

1,1

Comments

Suppose that r = (r(n)) is a sequence satisfying (i) 1 = r(1) > r(2) > r(3) > ... and (ii) r(n) -> 0. For x in (0,1], let n(1) be the index n such that r(n+1) , x <= r(n), and let L(1) = r(n(1))-r(n(1)+1). Let n(2) be the index n such that r(n(1)+1) < x <= r(n(1)+1) + L(1)r(n), and let L(2) = (r(n(2))-r(r(n)+1)L(1).

Continue inductively to obtain the sequence (n(1), n(2), n(3), ... ), the r-nested interval sequence of x. Taking r = (1/n!) gives the factorial-nested interval sequence of x.

Conversely, given a sequence s= (n(1),n(2),n(3),...) of positive integers, the number x having satisfying NI(x) = s is the sum of left-endpoints of nested intervals (r(n(k)+1), r(n(k))]; i.e., x = sum{L(k)r(n(k+1)+1), k >=1}, where L(0) = 1.

Guide to related sequences:

x factorial-nested interval sequence

1/e A269970

e-2 A269971

1/pi A269972

pi-3 A269973

sqrt(1/2) A269974

sqrt(2)-1 A269975

sqrt(1/3) A269976

sqrt(3)-1 A269977

1/tau A269978

A269979 (1,2,3,4,5,6,7,...)

A269980 (1,3,5,7,9,11,...)

A269981 (2,4,6,8,10,13,...)

Links

Table of n, a(n) for n=1..86.

Crossrefs

Cf. A000142, A269971-A269981.

Sequence in context: A183198 A249160 A346913 * A333518 A252230 A036043

Adjacent sequences: A269967 A269968 A269969 * A269971 A269972 A269973

Keyword

nonn,easy

Author

Clark Kimberling, Mar 08 2016

Status

approved