A269392 Permutation of natural numbers: a(1) = 1, a(2n) = A233271(1+a(n)), a(2n+1) = A269390(a(n)).

1, 2, 3, 4, 5, 7, 6, 8, 9, 12, 10, 16, 13, 15, 11, 21, 14, 24, 17, 32, 20, 28, 18, 49, 26, 38, 22, 46, 25, 31, 19, 64, 34, 42, 23, 79, 37, 53, 27, 110, 48, 63, 33, 94, 43, 56, 29, 186, 72, 87, 40, 128, 57, 71, 35, 174, 68, 82, 39, 106, 47, 60, 30, 245, 92, 117, 51, 152, 62, 75, 36, 322, 112, 127, 55, 203, 77, 90, 41

Offset

1,2

Comments

This sequence can be represented as a binary tree. Each left hand child is produced as A233271(1+n), and each right hand child as A269390(n), when the parent contains n:

|

...................1...................

2 3

4......../ \........5 7......../ \........6

/ \ / \ / \ / \

/ \ / \ / \ / \

/ \ / \ / \ / \

8 9 12 10 16 13 15 11

21 14 24 17 32 20 28 18 49 26 38 22 46 25 31 19

etc.

Links

Antti Karttunen, Table of n, a(n) for n = 1..3071

Index entries for sequences that are permutations of the natural numbers

Formula

a(1) = 1, a(2n) = A233271(1+a(n)), a(2n+1) = A269390(a(n)).

As a composition of other permutations:

a(n) = A269398(A269402(n)).

Prog

(Scheme, with memoization-macro definec)
(definec (A269392 n) (cond ((<= n 1) n) ((even? n) (A233271 (+ 1 (A269392 (/ n 2))))) (else (A269390 (A269392 (/ (- n 1) 2))))))

Crossrefs

Inverse: A269391.

Cf. A233271, A269390.

Cf. also A260432.

Similar or related permutations: A269398, A269402.

Sequence in context: A269391 A095903 A267112 * A166277 A344009 A145342

Adjacent sequences: A269389 A269390 A269391 * A269393 A269394 A269395

Keyword

nonn,base,tabf

Author

Antti Karttunen, Mar 05 2016

Status

approved