|
|
A269250
|
|
Number of times the digit 0 appears in the decimal expansion of n^3.
|
|
14
|
|
|
1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 3, 0, 0, 0, 0, 0, 1, 0, 0, 0, 3, 0, 1, 0, 0, 0, 0, 0, 0, 0, 3, 0, 0, 0, 1, 0, 0, 1, 0, 0, 3, 0, 1, 1, 0, 0, 0, 1, 1, 0, 3, 0, 2, 0, 0, 0, 0, 0, 0, 1, 3, 0, 0, 2, 0, 0, 0, 2, 0, 1, 3, 0, 0, 1, 1, 0, 0, 0, 0, 1, 3, 0, 0, 0, 1, 0, 1, 1, 0, 1, 3, 0, 0, 1, 1, 0, 0, 0, 0, 1, 6
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
0,11
|
|
COMMENTS
|
The cubes corresponding to the first occurrence of 1, 2, 3, ... are listed in A036527, i.e., A048365(n) = A036527(n)^(1/3) is the index of the first occurrence of n.
|
|
LINKS
|
|
|
EXAMPLE
|
1^3 = 1, 2^3 = 8, 3^3 = 27, 4^3 = 64, ..., 9^3 = 729 all have a(1) = a(2) = ... = a(9) = 0 digits '0'.
0^3 = 0 has a(0) = 1 digit '0'.
10^3 = 1000 has a(10) = 3 digits '0'.
|
|
MAPLE
|
seq(numboccur(0, convert(n^3, base, 10)), n=0..100); # Robert Israel, Feb 21 2016
|
|
MATHEMATICA
|
Table[DigitCount[n^3, 10, 0], {n, 0, 100}] (* Robert Price, Mar 21 2020 *)
|
|
PROG
|
(PARI) A269250(n)=!n+#select(t->!t, digits(n^3))
|
|
CROSSREFS
|
Analog for the other digits 1, ..., 9: A269241, A269242, A269243, A269244, A269245, A269246, A269247, A269248, A269249.
|
|
KEYWORD
|
nonn,base
|
|
AUTHOR
|
|
|
STATUS
|
approved
|
|
|
|