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%I #6 Feb 13 2016 23:17:37
%S 1,2,3,4,6,9,15,25,41,75,134,246,428,802,1454,2643,4588,8851,16849,
%T 32368,60504,117343
%N Number of iterations of A268395 needed to reach zero from 2^n + 1: a(n) = A268708(2^n + 1).
%F a(n) = A268708((2^n)+1).
%o (Scheme) (define (A268710 n) (A268708 (+ 1 (A000079 n))))
%Y Cf. A000051, A268395, A268708, A268709.
%K nonn,more
%O 0,2
%A _Antti Karttunen_, Feb 11 2016
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