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%I #79 May 07 2016 09:22:33
%S 6,9,22,26,44,52,73,111,122,164,201,214,254,311,374,398,465,521,542,
%T 617,684,774,899,969,1005,1064,1100,1181,1441,1548,1658,1694,1918,
%U 1977,2114,2255,2376,2537,2684,2727,3019,3068,3181,3238,3611,3985,4114,4182,4313
%N Number of primes p==1 (mod 3) for which A261029(2*prime(n)*p) is 4-i if prime(n)==i (mod 3), where i=1 or 2.
%e Let n=3, then prime(n)=5. Since 5==2(mod 3), then i=2. So a(3) is the number of primes p==1(mod 3) for which A261029(10*p)=4-2=2. So it is number of terms in A272381, i.e., a(3)=6.
%e Let n=4, then prime(n)=7. Since 7==1(mod 3), then i=1. So a(4) is the number of primes p==1(mod 3) for which A261029(14*p)=4-1=3. So it is number of terms in A272382, i.e., a(4)=9.
%Y Cf. A261029, A272381, A272382, A272384, A272404, A272406, A272407, A272409.
%K nonn
%O 3,1
%A _Vladimir Shevelev_ and _Peter J. C. Moses_, May 07 2016
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