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A267584
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a(0)=1; thereafter a(n) = 2^(1 + number of zeros in binary expansion of n).
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2
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1, 2, 4, 2, 8, 4, 4, 2, 16, 8, 8, 4, 8, 4, 4, 2, 32, 16, 16, 8, 16, 8, 8, 4, 16, 8, 8, 4, 8, 4, 4, 2, 64, 32, 32, 16, 32, 16, 16, 8, 32, 16, 16, 8, 16, 8, 8, 4, 32, 16, 16, 8, 16, 8, 8, 4, 16, 8, 8, 4, 8, 4, 4, 2, 128, 64, 64, 32, 64, 32, 32, 16, 64
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OFFSET
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0,2
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LINKS
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FORMULA
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For n >= 1, a(n) = 2^(1+A023416(n)).
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EXAMPLE
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12 = 1100 in binary, which contains two 0's, so a(12) = 2^3 = 8.
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MATHEMATICA
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Join[{1}, Table[2^(1+DigitCount[n, 2, 0]), {n, 80}]] (* Harvey P. Dale, Oct 08 2023 *)
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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