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A266688
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Number of partitions of n with product of multiplicities of parts equal to 5.
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2
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0, 0, 0, 0, 0, 1, 0, 1, 1, 1, 3, 3, 3, 4, 7, 8, 10, 12, 15, 18, 24, 28, 35, 42, 48, 60, 72, 84, 102, 120, 140, 166, 194, 226, 264, 311, 358, 416, 482, 554, 641, 738, 844, 970, 1112, 1271, 1450, 1654, 1878, 2138, 2429, 2748, 3116, 3524, 3976, 4493, 5065, 5696
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OFFSET
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0,11
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COMMENTS
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Also the number of partitions of n such that there is exactly one part which occurs 5 times, while all other parts occur only once.
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LINKS
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FORMULA
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G.f.: Sum_{k>=1} x^(5*k)/(1+x^k) * Product_{j>=1} (1+x^j).
a(n) ~ c * exp(Pi*sqrt(n/3)) / n^(1/4), where c = (12*log(2) - 7) / (8*3^(3/4)*Pi) = 0.023001573808... - Vaclav Kotesovec, May 24 2018
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EXAMPLE
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a(9) = 1: [1,1,1,1,1,4].
a(10) = 3: [2,2,2,2,2], [1,1,1,1,1,2,3], [1,1,1,1,1,5].
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MAPLE
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b:= proc(n, i, p) option remember; `if`(i*(p+(i-1)/2)<n, 0, `if`(n=0,
`if`(p=1, 1, 0), b(n, i-1, p) +add(`if`(irem(p, j)>0, 0, (h->
b(h, min(h, i-1), p/j))(n-i*j)), j=1..min(p, n/i))))
end:
a:= n-> b(n$2, 5):
seq(a(n), n=0..65);
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MATHEMATICA
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b[n_, i_, p_] := b[n, i, p] = If[i*(p + (i - 1)/2) < n, 0, If[n == 0, If[p == 1, 1, 0], b[n, i - 1, p] + Sum[If[Mod[p, j] > 0, 0, Function[h, b[h, Min[h, i - 1], p/j]][n - i*j]], {j, 1, Min[p, n/i]}]]];
a[n_] := b[n, n, 5];
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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