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Self-inverse permutation of natural numbers: a(n) = A250470(A030101(A250469(n))).
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%I #7 Jan 09 2016 16:08:47

%S 1,2,3,4,5,6,11,8,17,10,7,12,13,20,25,16,9,18,23,14,53,22,19,28,15,36,

%T 27,24,29,40,37,32,33,34,83,26,31,42,51,30,47,38,59,44,101,76,41,60,

%U 73,68,39,52,21,84,107,56,131,72,43,48,89,80,125,64,65,66,109,50,99,82,71,58,49,74,151,46,239,78,97,62,173,70,35,54

%N Self-inverse permutation of natural numbers: a(n) = A250470(A030101(A250469(n))).

%H Antti Karttunen, <a href="/A266404/b266404.txt">Table of n, a(n) for n = 1..4096</a>

%H <a href="/index/Per#IntegerPermutation">Index entries for sequences that are permutations of the natural numbers</a>

%F a(n) = A250470(A030101(A250469(n))) = A250470(A057889(A250469(n))).

%F Other identities. For all n >= 0:

%F A000035(a(n)) = A000035(n). [This permutation preserves the parity of n.]

%o (Scheme) (define (A266404 n) (A250470 (A030101 (A250469 n))))

%Y Cf. A000035, A030101, A057889, A250469, A250470.

%Y Cf. A265329, A266402 (other conjugates or similar derivations of A057889).

%Y Cf. also A266403.

%K nonn,base

%O 1,2

%A _Antti Karttunen_, Jan 02 2016