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 A265330 Zero-based row index to A265345; 2-adic valuation of bijective base-3 reversal of n: a(n) = A007814(A263273(n)). 4
 0, 1, 0, 2, 0, 1, 0, 3, 0, 1, 0, 2, 0, 1, 0, 4, 0, 1, 0, 2, 0, 1, 0, 3, 0, 1, 0, 2, 0, 1, 0, 6, 0, 1, 0, 2, 0, 1, 0, 3, 0, 1, 0, 2, 0, 1, 0, 4, 0, 1, 0, 2, 0, 1, 0, 3, 0, 1, 0, 2, 0, 1, 0, 5, 0, 1, 0, 2, 0, 1, 0, 3, 0, 1, 0, 2, 0, 1, 0, 4, 0, 1, 0, 2, 0, 1, 0, 3, 0, 1, 0, 2, 0, 1, 0, 6, 0, 1, 0, 2, 0, 1, 0, 4, 0, 1, 0, 2, 0, 1, 0, 4, 0, 1, 0, 2, 0, 1, 0, 3, 0, 1, 0, 2, 0, 1, 0, 3 (list; graph; refs; listen; history; text; internal format)
 OFFSET 1,4 LINKS Antti Karttunen, Table of n, a(n) for n = 1..6561 FORMULA a(n) = A007814(A263273(n)). a(2n+1) = 0, a(2n) = 1 + a(A265352(n)). EXAMPLE For n = 32, in base-3 "1012" [= A007089(32)], when we reverse it, we get "2101" [= A007089(64)], and 2-adic valuation of 64 [= "1000000" = A007088(64)] is 6, thus a(32) = 6. PROG (Scheme, two variants) (definec (A265330 n) (if (odd? n) 0 (+ 1 (A265330 (A265352 (/ n 2)))))) (define (A265330 n) (A007814 (A263273 n))) CROSSREFS One less than A265331. Cf. A007088, A007089, A263273, A265345, A265352. Cf. A265910 (corresponding other index). Cf. also A265336, A265337, A265340. Differs from A007814 for the first time at n=32, where a(32) = 6, while A007814(32) = 5. Sequence in context: A254990 A191255 A007814 * A272216 A320439 A321252 Adjacent sequences:  A265327 A265328 A265329 * A265331 A265332 A265333 KEYWORD nonn,base AUTHOR Antti Karttunen, Dec 18 2015 STATUS approved

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Last modified January 21 13:25 EST 2019. Contains 319350 sequences. (Running on oeis4.)