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A264965
Permutation of nonnegative integers: a(n) = A263273(A057889(n)).
13
0, 1, 2, 3, 4, 7, 6, 5, 8, 9, 10, 13, 12, 19, 22, 21, 16, 25, 18, 17, 20, 15, 26, 55, 24, 11, 14, 27, 28, 23, 30, 37, 64, 57, 46, 43, 36, 67, 70, 33, 40, 31, 66, 79, 52, 63, 38, 47, 48, 73, 58, 75, 76, 49, 54, 65, 56, 39, 34, 29, 60, 61, 74, 45, 32, 59, 42, 145, 68, 81, 226, 193, 72, 35, 82, 219, 100, 217, 174, 121, 80, 69
OFFSET
0,3
COMMENTS
Perform an adjusted reverse of n in base 2, followed by another adjusted reverse in base 3. "Adjusted reverse" here means the digit-reversing operation in which the tail of trailing zeros (in the base in question) is fixed, while the portion from the most significant digit to the least significant nonzero digit is reversed.
What percentage of the cycles are finite? (See the scatter-plot and A264969, also A264972, A264973.)
FORMULA
a(n) = A263273(A057889(n)).
Other identities. For all n >= 0:
A000035(a(n)) = A000035(n). [This permutation preserves the parity of n.]
PROG
(Scheme) (define (A264965 n) (A263273 (A057889 n)))
CROSSREFS
Inverse: A264966.
Cf. also A264967, A264968.
Sequence in context: A077223 A265369 A267308 * A266644 A329411 A055265
KEYWORD
nonn,base,look
AUTHOR
Antti Karttunen, Dec 05 2015
STATUS
approved