%I #16 Oct 02 2015 16:55:41
%S 1,2,3,3,4,3,5,8,6,8,3,7,15,3,8,15,3,9,24,6,10,24,6,5,11,35,6,5,12,35,
%T 9,5,13,48,9,5,14,48,9,12,15,63,12,12,5,16,63,12,12,5,17,80,12,12,5,
%U 18,80,15,21,5,19,99,15,21,5,20,99,15,21,10,21,120,18,21,10,7,22,120,18,32,10,7,23,143,18,32,10,7,24,143,21,32,10,7,25,168,21,32,15,7,26,168,21,45,15,7,27,195,24,45,15,16
%N Triangle read by rows T(n,k) in which column k lists the partial sums of the k-th column of triangle A261699.
%C Conjecture: the sum of row n gives A078471(n), the sum of all odd divisors of all positive integers <= n.
%C Row n has length A003056(n) hence column k starts in row A000217(k).
%C Column 1 gives A000027.
%e Triangle begins:
%e 1;
%e 2;
%e 3, 3;
%e 4, 3;
%e 5, 8;
%e 6, 8, 3;
%e 7, 15, 3;
%e 8, 15, 3;
%e 9, 24, 6;
%e 10, 24, 6, 5;
%e 11, 35, 6, 5;
%e 12, 35, 9, 5;
%e 13, 48, 9, 5;
%e 14, 48, 9, 12;
%e 15, 63, 12, 12, 5;
%e 16, 63, 12, 12, 5;
%e 17, 80, 12, 12, 5;
%e 18, 80, 15, 21, 5;
%e 19, 99, 15, 21, 5;
%e 20, 99, 15, 21, 10;
%e 21, 120, 18, 21, 10, 7;
%e 22, 120, 18, 32, 10, 7;
%e 23, 143, 18, 32, 10, 7;
%e 24, 143, 21, 32, 10, 7;
%e 25, 168, 21, 32, 15, 7;
%e 26, 168, 21, 45, 15, 7;
%e 27, 195, 24, 45, 15, 16;
%e ...
%e For n = 6 the sum of all odd divisors of all positive integers <= 6 is (1) + (1) + (1 + 3) + (1) + (1 + 5) + (1 + 3) = 17. On the other hand the sum of the 6th row of triangle is 6 + 8 + 3 = 17 equaling the sum of all odd divisors of all positive integers <= 6.
%Y Cf. A000027, A000217, A001227, A003056, A060831, A078471, A236104, A237593, A261699.
%K nonn,tabf
%O 1,2
%A _Omar E. Pol_, Sep 24 2015