

A262362


Real positive integers with more than one factorization in Z[sqrt(10)].


0



6, 9, 10, 12, 15, 18, 20, 24, 26, 27, 30, 36, 40, 42, 45, 48, 50, 52, 54, 60, 63, 66, 70, 72, 74, 75, 78, 80, 81, 84, 86, 90, 96, 99, 100, 102, 104, 105, 106, 108, 110, 111, 114, 117, 120, 126, 130, 132, 134, 135, 138, 140, 144, 148, 150, 153, 156, 159, 160, 162, 165, 166, 168, 170
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OFFSET

1,1


COMMENTS

To count as distinct from another factorization, a factorization must not be derived from the other by multiplication by units. For example, (4  sqrt(10))(4 + sqrt(10)) is not distinct from (1)(2  sqrt(10))(2 + sqrt(10)) as a factorization of 6 because 3  sqrt(10) is a unit and (2  sqrt(10))(3  sqrt(10)) = 4 + sqrt(10).
Given a number p that is prime in Z, if x^2 == 10 mod p has solutions in Z, then some multiples of p are in this sequence. If x is the smallest solution, then x^2  10 gives the smallest multiple of p in this sequence not divisible by any prior term. For example, 6^2 == 10 mod 13, and 26 = 2 * 13 = (6  sqrt(10))(6 + sqrt(10)).
If a number is in this sequence, then so are all its real positive integer multiples. The negative multiples also have more than one factorization, but of course one has to remember to put in the 1 as needed. Since Z[sqrt(10)] has units of norm 1, it is then possible to "shop" the units to include or exclude 1 from the factorization.
Z[sqrt(10)] has class number 2. This means that while a number may have more than one factorization, all factorizations have the same number of nonunit irreducible factors. If one factorization seems to have fewer factors, then it is an incomplete factorization.


LINKS

Table of n, a(n) for n=1..64.


EXAMPLE

9 = 3^2 = (1)(1  sqrt(10))(1 + sqrt(10)), so 9 is in the sequence.
10 = 2 * 5 = (sqrt(10))^2, so 10 is in the sequence.


CROSSREFS

Cf. A097955, A262828.
Sequence in context: A090466 A090428 A039725 * A125494 A177029 A105066
Adjacent sequences: A262359 A262360 A262361 * A262363 A262364 A262365


KEYWORD

nonn


AUTHOR

Alonso del Arte, Dec 23 2015


STATUS

approved



