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a(n) = (3^n)! / n!.
0

%I #13 Sep 08 2022 08:46:14

%S 1,6,181440,1814811575069725360128000000

%N a(n) = (3^n)! / n!.

%C Next term is too large to include.

%F a(n) = A079288(n)/A000142(n).

%e For n = 2, a(n) = (3^2)! / (2)! = 181440.

%t Table[(3^n)! / n!, {n, 0, 6}] (* _Vincenzo Librandi_, Sep 15 2015 *)

%o (PARI) a(n) = (3^n)! / n!;

%o vector(5, n, a(n-1))

%o (Magma) [Factorial(3^n) / Factorial(n): n in [0..6]]; // _Vincenzo Librandi_, Sep 15 2015

%Y Cf. A079288, A000142.

%K nonn

%O 0,2

%A _Altug Alkan_, Sep 14 2015