|
|
A261933
|
|
The first of two consecutive positive integers the sum of the squares of which is equal to the sum of the squares of seventeen consecutive positive integers.
|
|
4
|
|
|
40, 91, 2743, 6364, 192004, 445423, 13437571, 31173280, 940438000, 2181684211, 65817222463, 152686721524, 4606265134444, 10685888822503, 322372742188651, 747859530853720, 22561485688071160, 52339481270937931, 1578981625422792583, 3663015829434801484
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
1,1
|
|
COMMENTS
|
For the first of the corresponding seventeen consecutive positive integers, see A261935.
|
|
LINKS
|
|
|
FORMULA
|
G.f.: -x*(40*x^4+51*x^3-148*x^2+51*x+40) / ((x-1)*(x^4-70*x^2+1)).
|
|
EXAMPLE
|
40 is in the sequence because 40^2 + 41^2 = 5^2 + 6^2 + ... + 21^2.
|
|
MATHEMATICA
|
LinearRecurrence[{1, 70, -70, -1, 1}, {40, 91, 2743, 6364, 192004}, 20] (* Harvey P. Dale, Oct 17 2015 *)
|
|
PROG
|
(PARI) Vec(-x*(40*x^4+51*x^3-148*x^2+51*x+40)/((x-1)*(x^4-70*x^2+1)) + O(x^40))
|
|
CROSSREFS
|
|
|
KEYWORD
|
nonn,easy
|
|
AUTHOR
|
|
|
STATUS
|
approved
|
|
|
|