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Putative inverse of conjectured permutation in A261725.
2

%I #7 Sep 01 2015 03:41:37

%S 0,1,2,3,4,5,6,7,8,9,19,18,17,16,15,14,13,12,11,10,20,21,22,23,24,25,

%T 26,27,28,29,39,38,37,36,35,34,33,32,31,30,40,41,42,43,44,45,46,47,48,

%U 49,59,58,57,56,55,54,53,52,51,50,60,61,62,63,64,65,66,67

%N Putative inverse of conjectured permutation in A261725.

%C a(n) = A003100(n) for n < 100, but a(100) = 109, A003100(100) = 190.

%C a(n) = A118757(n) for n < 100, but a(100) = 109, A118757(100) = 190.

%C a(n) = A118758(n) for n < 201, but a(201) = 209, A118758(201) = 211.

%C a(n) = A174025(n) for n < 100, but a(100) = 109, A174025(100) = 199.

%C a(n) = A261725(n) for n < 100, but a(100) = 109, A261725(100) = 190.

%H Paul Tek, <a href="/A261729/b261729.txt">Table of n, a(n) for n = 0..10000</a>

%Y Cf. A261725.

%K nonn,base

%O 0,3

%A _Paul Tek_, Aug 30 2015