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A261416
Let b(k) denote A260273(k). It appears that for k >= 200, whenever b(k) just passes a power of 2, 2^m say, the successive differences b(k)-2^m converge to this sequence.
7
2, 5, 8, 11, 17, 20, 23, 29, 38, 43, 49, 54, 61, 70, 75, 81, 84, 87, 93, 102, 107, 114, 119, 128, 131, 136, 139, 145, 148, 151, 157, 167, 173, 180, 187, 196, 201, 206, 211, 218, 225, 230, 235, 244, 253, 262, 267, 273, 276, 279, 285, 294, 299, 305, 310, 317, 327, 333, 340, 343, 349, 358, 365, 372, 381
OFFSET
0,1
COMMENTS
It would be nice to have an independent characterization of this sequence.
A partial answer: set a(0)=2, and for n>0, a(n) = A261281(a(n-1)). - N. J. A. Sloane, Sep 17 2015
EXAMPLE
At k=200, b(k)=b(200)=1026 has just passed 2^10. The successive differences b(200+i)-2^10 (i>=0) beyond this point are 2, 5, 8, 11, 17, 20, 23, 29, 38, 43, 49, 54, 61, 70, 75, 81, 84, 87, 93, 102, 107, 114, 119, 128, 131, 136, 139, 145, 148, 151, 157, [165, ...], which are the first 31 terms of the present sequence.
At k=371, b(371)=2050, and the successive differences b(371+i)-2^11 are 2, 5, ..., 279, 285, ... giving the first 51 terms of the present sequence.
CROSSREFS
Cf. A260273, A261281. For when A260273 just passes a power of 2, see A261396.
Sequence in context: A032765 A375298 A340931 * A340386 A300272 A352143
KEYWORD
nonn
AUTHOR
N. J. A. Sloane, Aug 25 2015
STATUS
approved