OFFSET
0,1
COMMENTS
It would be nice to have an independent characterization of this sequence.
A partial answer: set a(0)=2, and for n>0, a(n) = A261281(a(n-1)). - N. J. A. Sloane, Sep 17 2015
EXAMPLE
At k=200, b(k)=b(200)=1026 has just passed 2^10. The successive differences b(200+i)-2^10 (i>=0) beyond this point are 2, 5, 8, 11, 17, 20, 23, 29, 38, 43, 49, 54, 61, 70, 75, 81, 84, 87, 93, 102, 107, 114, 119, 128, 131, 136, 139, 145, 148, 151, 157, [165, ...], which are the first 31 terms of the present sequence.
At k=371, b(371)=2050, and the successive differences b(371+i)-2^11 are 2, 5, ..., 279, 285, ... giving the first 51 terms of the present sequence.
CROSSREFS
KEYWORD
nonn
AUTHOR
N. J. A. Sloane, Aug 25 2015
STATUS
approved