

A261370


Permutation of nonnegative integers where a number having digits in nondescending order is followed by all numbers having the same digits arranged in increasing order.


5



0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 21, 13, 31, 14, 41, 15, 51, 16, 61, 17, 71, 18, 81, 19, 91, 20, 22, 23, 32, 24, 42, 25, 52, 26, 62, 27, 72, 28, 82, 29, 92, 30, 33, 34, 43, 35, 53, 36, 63, 37, 73, 38, 83, 39, 93, 40, 44, 45, 54, 46, 64, 47, 74, 48, 84
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OFFSET

0,3


COMMENTS

If a number contains a zero, then some permutation will yield a number with a leading zero, which is already in the sequence without the leading zero. So that permutation is not included. For example, 102 contains a zero, so 012 and 021 are permutations of these numbers' digits. But they are actually 12 and 21, which are already in the sequence. This leaves 120, 201 and 210 to be added to the sequence after 102.
From Rémy Sigrist, May 01 2017 : (Start)
 This sequence is to base 10 what A187769 is to base 2,
 Beyond the initial 0, this sequence can be seen as an irregular table, where the nth row corresponds to the permutation class of A179239(n).
(End)


LINKS

David A. Corneth, Table of n, a(n) for n = 0..10000


MATHEMATICA

a = {0}; f[n_] := Block[{w = Sort@ Permutations@ IntegerDigits@ n}, w = Delete[w, Position[First /@ w, 0]]]; Do[If[! MemberQ[a, n], AppendTo[a, FromDigits /@ f@ n]], {n, 105}]; DeleteDuplicates@ Flatten@ a (* Michael De Vlieger, Sep 07 2015 *)


CROSSREFS

Cf. A009994, A179239, A187769.
Sequence in context: A262356 A277861 A173902 * A257737 A130577 A252490
Adjacent sequences: A261367 A261368 A261369 * A261371 A261372 A261373


KEYWORD

nonn,base,look


AUTHOR

David A. Corneth, Aug 17 2015


STATUS

approved



