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A260896 a(n) gives the number of integers m such that there exist k and h with 2n^2 < mk^2 < 2(n+1)^2 and 2n^2 < 2mh^2 < 2(n+1)^2. 1

%I #13 Mar 24 2017 00:47:58

%S 0,1,0,1,1,1,3,3,2,3,2,2,3,3,0,3,1,4,2,3,3,1,6,3,4,4,5,3,2,5,4,8,4,4,

%T 5,1,5,6,4,5,3,6,2,5,7,5,8,4,7,4,7,7,7,10

%N a(n) gives the number of integers m such that there exist k and h with 2n^2 < mk^2 < 2(n+1)^2 and 2n^2 < 2mh^2 < 2(n+1)^2.

%C A072905(2n^2) > A006255(2n^2) and A066400(2n^2) > 2 for all n such that a(n) > 0.

%C Conjecture: a(n) > 0 for all n > 14.

%H Peter Kagey, <a href="/A260896/b260896.txt">Table of n, a(n) for n = 0..10000</a>

%e For n=12 the a(12)=3 solutions are 3, 6, and 37:

%e (1) (a) 2 * 12^2 < 3 * 10^2 < 2 * 13^2

%e (b) 2 * 12^2 < 2 * 3 * 7^2 < 2 * 13^2

%e (2) (a) 2 * 12^2 < 6 * 7^2 < 2 * 13^2

%e (b) 2 * 12^2 < 2 * 6 * 5^2 < 2 * 13^2

%e (3) (a) 2 * 12^2 < 37 * 3^2 < 2 * 13^2

%e (b) 2 * 12^2 < 2 * 37 * 2^2 < 2 * 13^2

%Y Cf. A006255, A066400, A072905.

%K nonn

%O 0,7

%A _Peter Kagey_, Aug 03 2015

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Last modified April 25 16:23 EDT 2024. Contains 371989 sequences. (Running on oeis4.)