A259005 Number of (n+2)X(7+2) 0..1 arrays with every 3X3 subblock sum of the two medians of the central row and column plus the two sums of the diagonal and antidiagonal nondecreasing horizontally, vertically and ne-to-sw antidiagonally

914320, 701282, 2005182, 1284465, 431280, 390714, 73734, 61001, 59336, 60827, 60804, 61979, 62070, 63065, 63258, 63274, 64258, 64949, 65852, 66119, 65838, 67774, 67880, 69079, 69174, 70169, 70362, 70378, 71362, 72053, 72956, 73223, 72942, 74878

Offset

1,1

Comments

Column 7 of A259006

Links

R. H. Hardin, Table of n, a(n) for n = 1..210

Formula

Empirical: a(n) = a(n-1) +a(n-12) -a(n-13) for n>25

Empirical for n mod 12 = 0: a(n) = 592*n + 54871 for n>12

Empirical for n mod 12 = 1: a(n) = 592*n + 54374 for n>12

Empirical for n mod 12 = 2: a(n) = 592*n + 54777 for n>12

Empirical for n mod 12 = 3: a(n) = 592*n + 54378 for n>12

Empirical for n mod 12 = 4: a(n) = 592*n + 53802 for n>12

Empirical for n mod 12 = 5: a(n) = 592*n + 54194 for n>12

Empirical for n mod 12 = 6: a(n) = 592*n + 54293 for n>12

Empirical for n mod 12 = 7: a(n) = 592*n + 54604 for n>12

Empirical for n mod 12 = 8: a(n) = 592*n + 54279 for n>12

Empirical for n mod 12 = 9: a(n) = 592*n + 53406 for n>12

Empirical for n mod 12 = 10: a(n) = 592*n + 54750 for n>12

Empirical for n mod 12 = 11: a(n) = 592*n + 54264 for n>12

Example

Some solutions for n=1
..0..0..0..0..0..1..0..1..1....0..0..0..0..1..0..1..1..1
..0..0..0..0..0..1..0..1..0....1..0..1..0..1..0..0..0..0
..1..1..0..0..1..1..0..0..1....1..1..1..0..1..1..1..1..0

Crossrefs

Cf. A259006

Sequence in context: A253998 A258908 A259012 * A256903 A185532 A360907

Adjacent sequences: A259002 A259003 A259004 * A259006 A259007 A259008

Keyword

nonn

Author

R. H. Hardin, Jun 16 2015

Status

approved