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 A258075 Constant x that satisfies: x = Sum_{n>=1} frac(n*(1-x)) / 2^n. 1
 0, 4, 4, 3, 5, 7, 4, 6, 9, 0, 1, 5, 0, 0, 3, 2, 6, 1, 5, 7, 8, 6, 0, 4, 0, 4, 4, 3, 5, 7, 4, 6, 9, 0, 1, 5, 0, 0, 3, 2, 5, 8, 5, 1, 1, 4, 3, 0, 2, 6, 5, 3, 0, 3, 8, 8, 1, 2, 5, 7, 7, 4, 6, 2, 8, 4, 3, 1, 2, 5, 3, 1, 6, 4, 8, 5, 9, 0, 0, 2, 2, 3, 4, 3, 0, 2, 5, 3, 7, 5, 8, 8, 5, 2, 7, 8, 2, 4, 8, 5, 9, 9, 1, 9, 5, 8, 2, 4, 2, 9, 2, 7, 1, 5, 6, 9, 5, 0, 4, 3, 3, 1, 0, 9, 7, 8, 1, 3, 6, 1, 1, 9, 6, 0, 1, 8, 3, 1, 0, 4, 9, 5, 5, 4, 6, 2, 3, 2, 2, 6, 0, 2 (list; constant; graph; refs; listen; history; text; internal format)
 OFFSET 1,2 COMMENTS A good approximation to this constant is 680/1533, which is correct to 39 digits. LINKS Eric Weisstein, Devil's Staircase from MathWorld. FORMULA This constant satisfies: (1) 1 = x + Sum_{n>=1} {n*x} / 2^n, where {z} denotes the fractional part of z. (2) 1 = 3*x - Sum_{n>=1} [n*x] / 2^n, where [z] denotes the integer floor of z. (3) 1 = 3*x - Sum_{n>=1} 1 / 2^[n/x], a "devil's staircase" sum. (4) 2 = 3*x + Sum_{n>=1} 1 / 2^[n/(1-x)], a "devil's staircase" sum. EXAMPLE x = 0.4435746901500326157860404435746901500325851143026... where x = Sum_{n>=1} {n*(1-x)} / 2^n such that x < 1/2 and x > 0. Other series involving x begin: (a) 3*x-1 = 0/2 + 0/2^2 + 1/2^3 + 1/2^4 + 2/2^5 + 2/2^6 + 3/2^7 + 3/2^8 + 3/2^9 + 4/2^10 + 4/2^11 + 5/2^12 + 5/2^13 + 6/2^14 +...+ [n*x]/2^n +... (b) 2-3*x = 0/2 + 1/2^2 + 1/2^3 + 2/2^4 + 2/2^5 + 3/2^6 + 3/2^7 + 4/2^8 + 5/2^9 + 5/2^10 + 6/2^11 + 6/2^12 + 7/2^13 + 7/2^14 +...+ [n*(1-x)]/2^n +... (c) 3*x-1 = 1/2^2 + 1/2^4 + 1/2^6 + 1/2^9 + 1/2^11 + 1/2^13 + 1/2^15 + 1/2^18 + 1/2^20 + 1/2^22 + 1/2^24 + 1/2^27 + 1/2^29 +...+ 1/2^[n/x] +... (d) 2-3*x = 1/2^1 + 1/2^3 + 1/2^5 + 1/2^7 + 1/2^8 + 1/2^10 + 1/2^12 + 1/2^14 + 1/2^16 + 1/2^17 + 1/2^19 + 1/2^21 + 1/2^23 +...+ 1/2^[n/(1-x)] +... note that (c) and (d) involve Beatty sequences as exponents of 1/2. The complement to this constant is A258072: 1-x = 0.5564253098499673842139595564253098499674148856973... and possesses very similar properties. The CONTINUED FRACTION of 3*x has large partial quotients: 3*x = [1, 3, 42, 4, 41619663273108911871743469597819008, 10889035741470030830827987437816582767104, ...]; the number of digits of the partial quotients begin: [1, 1, 2, 1, 35, 41, 115, 270, ...]. The initial 1050 digits are: x = 0.44357469015003261578604044357469015003258511430265\ 30388125774628431253164859002234302537588527824859\ 91958242927156950433109781361196018310495546232260\ 21308756488922508493146400309145266931418310463207\ 21682655581705538047690626270645407928462460161012\ 59348074253641658104334540972276437282369203087870\ 91688278965124501135824721922196014571344903077739\ 18500944407821228291964676297532896809047816970961\ 57232314116611612205997186868899794801384103713379\ 27093301379877141640033100637461650643685872664216\ 71210915983869597104515647764570759665860825582616\ 02202386683742093208255873853725828394394746230649\ 17646005634235224736778439225789268521850715113549\ 81826246824173592162652534369620590399778082914397\ 59525545391741573753969070145840793634947962855349\ 40161700909555769785319066569343646229986269080724\ 03331326445769921119003906381638002817964787631913\ 86332217342163925996090891887058572086607050246768\ 90125594710389427906358536708700202340858220467421\ 83637059019834780162093855868315000246318027150733\ 19542694230313602926455823852338591379348725144367... PROG (PARI) {x=.4; for(i=1, 100, x = (x + sum(n=1, 4000, frac(n*(1-x))/2^n*1.))/2); x} (PARI) /* Series 2-3*x = Sum_{n>=1} 1 / 2^[n/(1-x)] gives faster convergence: */ {x=0.4; for(i=1, 10, x = (2 - sum(n=1, 2000, 1./2^floor(n/(1-x))))/3 ); x} CROSSREFS Cf. A258072. Sequence in context: A073321 A055620 A072420 * A286296 A023530 A233581 Adjacent sequences:  A258072 A258073 A258074 * A258076 A258077 A258078 KEYWORD nonn,cons AUTHOR Paul D. Hanna, May 21 2015 STATUS approved

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Last modified April 19 04:19 EDT 2019. Contains 322237 sequences. (Running on oeis4.)